3.636 \(\int x^2 (a+b x^4)^3 \, dx\)

Optimal. Leaf size=43 \[ \frac {a^3 x^3}{3}+\frac {3}{7} a^2 b x^7+\frac {3}{11} a b^2 x^{11}+\frac {b^3 x^{15}}{15} \]

[Out]

1/3*a^3*x^3+3/7*a^2*b*x^7+3/11*a*b^2*x^11+1/15*b^3*x^15

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Rubi [A]  time = 0.01, antiderivative size = 43, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {270} \[ \frac {3}{7} a^2 b x^7+\frac {a^3 x^3}{3}+\frac {3}{11} a b^2 x^{11}+\frac {b^3 x^{15}}{15} \]

Antiderivative was successfully verified.

[In]

Int[x^2*(a + b*x^4)^3,x]

[Out]

(a^3*x^3)/3 + (3*a^2*b*x^7)/7 + (3*a*b^2*x^11)/11 + (b^3*x^15)/15

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rubi steps

\begin {align*} \int x^2 \left (a+b x^4\right )^3 \, dx &=\int \left (a^3 x^2+3 a^2 b x^6+3 a b^2 x^{10}+b^3 x^{14}\right ) \, dx\\ &=\frac {a^3 x^3}{3}+\frac {3}{7} a^2 b x^7+\frac {3}{11} a b^2 x^{11}+\frac {b^3 x^{15}}{15}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 43, normalized size = 1.00 \[ \frac {a^3 x^3}{3}+\frac {3}{7} a^2 b x^7+\frac {3}{11} a b^2 x^{11}+\frac {b^3 x^{15}}{15} \]

Antiderivative was successfully verified.

[In]

Integrate[x^2*(a + b*x^4)^3,x]

[Out]

(a^3*x^3)/3 + (3*a^2*b*x^7)/7 + (3*a*b^2*x^11)/11 + (b^3*x^15)/15

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fricas [A]  time = 0.65, size = 35, normalized size = 0.81 \[ \frac {1}{15} x^{15} b^{3} + \frac {3}{11} x^{11} b^{2} a + \frac {3}{7} x^{7} b a^{2} + \frac {1}{3} x^{3} a^{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x^4+a)^3,x, algorithm="fricas")

[Out]

1/15*x^15*b^3 + 3/11*x^11*b^2*a + 3/7*x^7*b*a^2 + 1/3*x^3*a^3

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giac [A]  time = 0.15, size = 35, normalized size = 0.81 \[ \frac {1}{15} \, b^{3} x^{15} + \frac {3}{11} \, a b^{2} x^{11} + \frac {3}{7} \, a^{2} b x^{7} + \frac {1}{3} \, a^{3} x^{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x^4+a)^3,x, algorithm="giac")

[Out]

1/15*b^3*x^15 + 3/11*a*b^2*x^11 + 3/7*a^2*b*x^7 + 1/3*a^3*x^3

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maple [A]  time = 0.00, size = 36, normalized size = 0.84 \[ \frac {1}{15} b^{3} x^{15}+\frac {3}{11} a \,b^{2} x^{11}+\frac {3}{7} a^{2} b \,x^{7}+\frac {1}{3} a^{3} x^{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(b*x^4+a)^3,x)

[Out]

1/3*a^3*x^3+3/7*a^2*b*x^7+3/11*a*b^2*x^11+1/15*b^3*x^15

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maxima [A]  time = 1.24, size = 35, normalized size = 0.81 \[ \frac {1}{15} \, b^{3} x^{15} + \frac {3}{11} \, a b^{2} x^{11} + \frac {3}{7} \, a^{2} b x^{7} + \frac {1}{3} \, a^{3} x^{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x^4+a)^3,x, algorithm="maxima")

[Out]

1/15*b^3*x^15 + 3/11*a*b^2*x^11 + 3/7*a^2*b*x^7 + 1/3*a^3*x^3

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mupad [B]  time = 0.04, size = 35, normalized size = 0.81 \[ \frac {a^3\,x^3}{3}+\frac {3\,a^2\,b\,x^7}{7}+\frac {3\,a\,b^2\,x^{11}}{11}+\frac {b^3\,x^{15}}{15} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(a + b*x^4)^3,x)

[Out]

(a^3*x^3)/3 + (b^3*x^15)/15 + (3*a^2*b*x^7)/7 + (3*a*b^2*x^11)/11

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sympy [A]  time = 0.08, size = 39, normalized size = 0.91 \[ \frac {a^{3} x^{3}}{3} + \frac {3 a^{2} b x^{7}}{7} + \frac {3 a b^{2} x^{11}}{11} + \frac {b^{3} x^{15}}{15} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(b*x**4+a)**3,x)

[Out]

a**3*x**3/3 + 3*a**2*b*x**7/7 + 3*a*b**2*x**11/11 + b**3*x**15/15

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